Q1a: 4589
Q1b: would be 20 outs to hit the stright
Q2a: ???
Q2b: ???
Q3: Antanas 'Tony G' Guoga
Q4: Dusk Till Dawn Poker Club (Casino in Lenton, England, United Kingdom)
Q5: the lowest-ranked community card
Q6a: "World Poker Tour", Travel Channel
Q6b: U.S.A.
Q7a: AFAIK -> acronym of "as far as I know."
Q7b: ???
Q7c: I found more than one in which bob use AFAIK (in fact he used afaiks) and have more than 500 views:
What is your favorite poker forum?
What is your favorite poker forum?
The Free Roll Whore Problem
How many hours a day do you play?
AA against AT
Q8a: 168.568.545.600 to 1
Q8b:
Our first case: first to fourth player hit AKs
Prob. first player to hit an Ace (any suit): 4/52
Prob. first player to hit a K (same suit than Ace): 1/51
Prob. second player to hit an Ace (any suit): 3/50
Prob. second player to hit a K (same suit than Ace): 1/49
Prob. third player to hit an Ace (any suit): 2/48
Prob. third player to hit a K (same suit than Ace): 1/47
Prob. fourth player to hit an Ace (only one on deck): 1/46
Prob. fourth player to hit a K (same suit than Ace): 1/45
Prob. fifth player to hit any card except A or K: 44/44
Prob. fifth player to hit any card except A or K: 43/43
Prob. sixth player to hit any card except A or K: 42/42
Prob. sixth player to hit any card except A or K: 41/41
A=(4*3*2*44*43*42*41)/(52*51*50*49*48*47*46*45*44*43*42*41)
A=(4*3*2)/(52*51*50*49*48*47*46*45)
Another case: Lets say that 1st, 3th, 4th, and 6th players hit AKs
Prob. first player to hit an Ace (any suit): 4/52
Prob. first player to hit a K (same suit than Ace): 1/51
Prob. second player to hit any card except A or K:: 44/50
Prob. second player to hit any card except A or K:: 43/49
Prob. third player to hit an Ace (any suit): 3/48
Prob. third player to hit a K (same suit than Ace): 1/47
Prob. fourth player to hit an Ace (only one on deck): 2/46
Prob. fourth player to hit a K (same suit than Ace): 1/45
Prob. fifth player to hit any card except A or K: 42/44
Prob. fifth player to hit any card except A or K: 41/43
Prob. sixth player to hit an Ace (only one on deck): 1/46
Prob. sixth player to hit a K (same suit than Ace): 1/45
A=(4*3*2*44*43*42*41)/(52*51*50*49*48*47*46*45*44*43*42*41)
A=(4*3*2)/(52*51*50*49*48*47*46*45)
(the same number)
The 4 players could be sitted in any position in a six seat holdem table, so we need to multiply this number (A) and the possible combinations:
( C(n,x) = n! / (n - x)! x! .... (n >= x ) )
X=A*C(6,4)=A*(6!/4!(6-4)!)=A*15
X=(15*4*3*2)/52*51*50*49*48*47*46*45)=1/(26*51*25*49*48*47*46) = 1/168.568.545.600
Q9: Poker's chips
Q10: Phil Ivey
Q11: The one who holds spades
Q12.1: Gus Hansen
Q12.2: John Juanda
Q12.3: Freddy Deeb
Q12.4: John Hennigan
Q12.5: Chris Bigler
Q12.6: Scotty Nguyen